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logb(xy) = logb(x) + logb(y)
log \( _b ({x \over y}) \) = logb(x) - logb(y)
logb(xd) = d logb(x)
logb\( \sqrt[x]{y} \) = \( {log _b(x)} \over y \)
c logb(x) + d logb(y) = logb(xcyd)
Changing the Base
logba = \( {log _d(a)} \over {log _d(b)} \)
Changing the Base
logb(a + c) = logba \( {log _b(1 + {c \over a})} \)
logb(a - c) = logba \( {log _b(1 - {c \over a})} \)
Exponents
x log(log(x))\log(x) = log(x)
Exercise : Logarithm MCQ Questions and Answers
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