Formulae
1. Speed, Time and Distance
Speed = (Distance/Time)
Time = (Distance/Speed)
Distance = (Speed x Time).
2. km per hr to m per sec conversion x km/hr = (x*5/18) m/sec.
3. m/sec to km/hr conversion x m/sec = (x *18/5) km/hr.
Exercise : Time and Distance MCQ Questions and Answers
Question 1
Walking 6/7th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is :
| A. |
| B. |
| C. |
| D. |
Correct Answer : C. 1 hour 12 min.
Description :
New speed = 6/7 of usual speed.
New time = 7/6 of usual time.
(7/6 of usual time) - (usual time) = 1/5 hour.
Therefore, 1/6 of usual time = 1/5 hour
Usual time = 6/5 hours = 1 hour 12 min.
View Answer
50/50
Workspace
Report
Discuss
Question 2
One of the two buses completes a journey of 300 km in 15/2 hours and the other a journey of 450 km in 9 hours. The ratio of their average speeds is
| A. |
| B. |
| C. |
| D. |
Correct Answer : D. 4:5
Description :
No answer description available for this question. Let us discuss.
Question 3
A man crosses a street 600 m long in 5 minutes. His speed in km. per hour is:
| A. |
| B. |
| C. |
| D. |
Correct Answer : B. 7.2
Description :
Distance=600m
Time=5 min = 5\times 60 sec
Speed = Distance/Time
⇒ 600/(5×60) m/sec
⇒ 2 m/sec
⇒ 2× 18/5 = 7.2 Km/hr
Question 4
A train T1, left station S1 for station S2 at 11:00 am at speed of 72 kmph. Another train T2 left station S2 for S1 at 10:00 am at a speed of 108 kmph. At what time would the trains be 24 km apart for
| A. |
| B. |
| C. |
| D. |
Correct Answer : C. 11:36 am
Description :
No answer description available for this question. Let us discuss.
Question 5
A bus left P for Q and travelled at an average speed of 40 kmph and reached Q one hour later than the scheduled time, Had the bus travelled at an average speed of 60 kmph, it would have reached Q one
| A. |
| B. |
| C. |
| D. |
Correct Answer : C. 48 kmph
Description :
Let the distance between P and Q be d km, and the required time be t hours.
(d/40) - 1 = (d/60) + 1 = t =? (d/40) - (d/60) = 2
=? d(60 - 40) = 4800 =? d = 240 km.
So, t = (240/40) - 1 = 5 hours
Therefore , required speed = 240/5 = 48 kmph.
Question 6
An express train travelled at an average speed of 100 km/hr, stopping for 3 minutes after every 75 km. How long did it take to reach its destination 600 km from the starting point?
| A. |
| B. |
| C. |
| D. |
Correct Answer : C. 6 hrs 21 min
Description :
No answer description available for this question. Let us discuss.
Question 7
A motorist travels for 6 hours, the first half at 60 Kmph and the rest at 48 Kmph. Find the distance Traveled by him.
| A. |
| B. |
| C. |
| D. |
Correct Answer : D. 324 Km
Description :
No answer description available for this question. Let us discuss.
Question 8
A 220m long train passes a signal post in 12s. Find the speed of the train?
| A. |
| B. |
| C. |
| D. |
Correct Answer : A. 66 km/h
Description :
No answer description available for this question. Let us discuss.
Question 9
Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
| A. |
| B. |
| C. |
| D. |
Correct Answer : B. 12 min
Description :
T = 9/45 * 60 = 12
Question 10
A man rows a boat 18 kilometres in 4 hours downstream and returns upstream in 12 hours. The speed of the stream (in km per hour) is
| A. |
| B. |
| C. |
| D. |
Correct Answer : A. 1.5
Description :
No answer description available for this question. Let us discuss.